Functional isomers are compounds that have the same molecular formula but different functional groups.
1. Option (A): \( \text{CH}_3\text{COOH} \) is acetic acid (carboxylic acid), and \( \text{HCOOCH}_3 \) is methyl formate (ester). These are functional isomers because they have different functional groups: carboxylic acid and ester.
2. Option (B): \( \text{C}_2\text{H}_5\text{OC}_2\text{H}_5 \) is ethyl ether, and \( \text{C}_3\text{H}_7\text{OCH}_3 \) is methoxypropane. These compounds are not functional isomers; they have different molecular formulas and hence are not functional isomers.
3. Option (C): \( \text{CH}_3\text{CH}_2\text{OH} \) is ethanol (alcohol), and \( \text{CH}_3\text{OCH}_3 \) is dimethyl ether (ether). These are functional isomers because they have the same molecular formula but different functional groups: alcohol and ether.
4. Option (D): \( \text{CH}_3\text{CH}_2\text{NO}_2 \) is nitroethane, and \( \text{H}_2\text{NCH}_2\text{COOH} \) is glycine. These are functional isomers because they have different functional groups: nitro group and amino acid group. Thus, the correct answer is (B), as \( \text{C}_2\text{H}_5\text{OC}_2\text{H}_5 \) and \( \text{C}_3\text{H}_7\text{OCH}_3 \) are not functional isomers.
The correct option is (B): \(C_2H_5OC_2H_5\) and \(C_3H_7OCH_3\)
The incorrect statements regarding geometrical isomerism are:
(A) Propene shows geometrical isomerism.
(B) Trans isomer has identical atoms/groups on the opposite sides of the double bond.
(C) Cis-but-2-ene has higher dipole moment than trans-but-2-ene.
(D) 2-methylbut-2-ene shows two geometrical isomers.
(E) Trans-isomer has lower melting point than cis isomer.
Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II): are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below: