Question:

Which of the following is not a non-linear partial differential equation, where p=zxandq=zy?p = \frac{\partial z}{\partial x} \quad \text{and} \quad q = \frac{\partial z}{\partial y}?

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In non-linear partial differential equations the derivatives of the function are raised to powers or multiplied together
Updated On: Dec 30, 2024
  • p+q=pq p + q = pq
  • x2p2+y2q2=z2 x^2p^2 + y^2q^2 = z^2
  • (x+y)(zx+zy)2+(xy)(zxzy)2=1 (x + y)\left(\frac{\partial z}{\partial x} + \frac{\partial z}{\partial y}\right)^2 + (x - y)\left(\frac{\partial z}{\partial x} - \frac{\partial z}{\partial y}\right)^2 = 1
  • 2zx2+2zxy62zy2=x2sin(x+y) \frac{\partial^2 z}{\partial x^2} + \frac{\partial^2 z}{\partial x \partial y} - 6 \frac{\partial^2 z}{\partial y^2} = x^2 \sin(x + y)
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The Correct Option is D

Solution and Explanation

The equation in option 4 is a linear partial differential equation as it only involves second-order derivatives with respect to x and y and does not contain terms where p and q are multiplied The other equations are non-linear due to the presence of terms like pq or powers of p and q
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