Which of the following is most powerful oxidising agent?
- $ I_{2} $
- $ Cl_{2}$
- $ Br_{2}$
- $ F_{2} $
The Correct Option is D
Approach Solution - 1
Approach Solution -2
The most effective oxidizer is Fluorine, having the biggest (+) electrode potential. Fluorine is the most powerful elemental oxidizing agent.
This happens because fluorine is the most electronegative element in the current periodic table, and hence has the highest active force on electrons of all the ingredients.
Oxidizing agents are normally located in their most oxidized states. Ions, atoms, and molecules with high electron affinity are known as good oxidizers. The bigger the oxidizing power, the stronger the electron affinity.
Oxidizing materials can increase the spread of fire and make it more strong. Substances that don't normally burn well in the air are able to burn quickly. Without visible elements, fuel materials are stimulated to fire at random.
Hence, the correct option is (D) F
Top Questions on trends in periodic table
- The correct statements from the following are:
(A) The decreasing order of atomic radii of group 13 elements is Tl $>$ In $>$ Ga $>$ Al $>$ B.
(B) Down the group 13 electronegativity decreases from top to bottom.
(C) Al dissolves in dil. HCl and liberate H$_2$, but conc. HNO$_3$ renders Al passive by forming a protective oxide layer on the surface.
(D) All elements of group 13 exhibits highly stable +1 oxidation state.
(E) Hybridisation of Al in [Al(H$_2$O)$_6$]$^{3+}$ ion is sp$^3$d$^2$.
Choose the correct answer from the options given below.- JEE Main - 2024
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- Given below are two statements:
Statement I: The metallic radius of Na is 1.86 Å and the ionic radius of Na$^+$ is lesser than 1.86 Å.
Statement II: Ions are always smaller in size than the corresponding elements.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2024
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- Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Both rhombic and monoclinic sulphur exist as S$_8$ while oxygen exists as O$_2$.
{Reason (R): Oxygen forms $p\pi$-$p\pi$ multiple bonds with itself and other elements having small size and high electronegativity like C, N, which is not possible for sulphur.
In the light of the above statements, choose the most appropriate answer from the options given below:- JEE Main - 2024
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- Match List I with List II List I(Atomic number)List II(Block of periodic table)A37Ip - blockB78IId - blockC52IIIf - blockD65IVs - block Choose the correct answer from the options given below:
- JEE Main - 2023
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- Given below are two statements :
Statement I : The decrease in first ionization enthalpy from B to Al is much larger than that from Al to Ga.
Statement II : The d orbitals in Ga are completely filled. In the light of the above statements,
choose the most appropriate answer from the options given below- JEE Main - 2023
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Concepts Used:
Trends in Periodic Table
The following trend in periodic properties of elements is observed:
Atomic size Trends:
The distance between the centre of the nucleus and the outermost shell of an atom is known as the atomic radius. In a group the atomic size increases due to the addition of shells as we move from one period to another. Across a period the atomic size decreases as the number of shells remain the same while the nuclear charge increases.
Metallic character Trends:
The elements which lose electrons to form cations are known as metals. Metallic character increases as we move down the group because the atomic size increases which lead to easy loss of electrons. On the other hand, it decreases across a period as we move from left to right.
Non-metallic character Trends:
The elements which have a tendency to gain electrons are known as non-metals. The tendency to gain electrons increases on moving across a period due to an increase in the nuclear charge and decrease in the atomic size. Hence, non-metallic character increases across a period.
Ionization potential Trends:
Ionization potential is defined as the amount of energy required to remove an electron from the outermost shell of a gaseous atom and convert it into a positively charged gaseous ion. The periodic properties in terms of ionization potential increase because the atomic size decreases across a period due to increase in the nuclear charge.
Melting Point Trends:
The melting point of an element is basically the energy required to change the state of an element from its solid state to its liquid state. Which essentially implies breaking a few bonds. Thus, higher the stronger the bond between the atoms, higher will be the melting point.