Group–13 elements react with \( O_2 \) in amorphous form to form oxides of type \( M_2O_3 \) (M = element). Which among the following is the most basic oxide?
Tl2O3
Tl2O2
Cr2O3
B2O3
The Correct Option is B
Approach Solution - 1
Tl+ oxide is more basic than \(Tl_3\)+ \(Cr_2O_3\) is amphoteric.
Approach Solution -2
Out of Tl2O3 and Tl2O2, Tl2O2 is expected to be more basic because it has a higher oxidation state of +1 for Tl as compared to +3 in Tl2O3. Higher oxidation state of the metal in an oxide generally leads to a more basic oxide.
Therefore, Tl2O2 is the most basic among the given options.
Answer. B
Approach Solution -3
As electropositive character increases, basic character of oxide increases: \[ B_2O_3 < Al_2O_3 < Ga_2O_3 < In_2O_3 < Tl_2O_3 \] % Correct Answer Correct Answer:} (4) B\(_2\)O\(_3\)
Top Questions on Amines
Amines are usually formed from amides, imides, halides, nitro compounds, etc. They exhibit hydrogen bonding which influences their physical properties. In alkyl amines, a combination of electron releasing, steric and H-bonding factors influence the stability of the substituted ammonium cations in protic polar solvents and thus affect the basic nature of amines. Alkyl amines are found to be stronger bases than ammonia. Amines being basic in nature, react with acids to form salts. Aryldiazonium salts, undergo replacement of the diazonium group with a variety of nucleophiles to produce aryl halides, cyanides, phenols and arenes.
How can you convert the following:
(i) Ethanoic acid to methanamine- Write short notes on the following:
(i) Carbylamine reaction
(ii) Hofmann–bromamide reaction
(iii) Diazotisation - The purification method based on the following physical transformation is: \[ {Solid} \xrightarrow{{Heat}} {Vapour} \xrightarrow{{Cool}} {Solid} \]
The total number of compounds from below when treated with hot KMnO4 giving benzoic acid is:
- Identify correct statements: (A) Primary amines do not give diazonium salts when treated with \({NaNO}_2\) in acidic condition.
(B) Aliphatic and aromatic primary amines on heating with \({CHCl}_3\) and ethanolic \({KOH}\) form carbylamines.
(C) Secondary and tertiary amines also give carbylamine test.
(D) Benzenesulfonyl chloride is known as Hinsberg’s reagent.
(E) Tertiary amines react with benzenesulfonyl chloride very easily.
Choose the correct answer from the options given below:
Questions Asked in JEE Main exam
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Concepts Used:
Amines - Chemical Properties
There are many chemical properties of amines.
The primary and secondary amines, including several amine derivatives, have a direct impact on their properties due to the presence of hydrogen bonding. The compounds containing phosphorus have a lower boiling point and the compounds containing amines and alcohol have a higher boiling point. The structure of alkanols is immensely similar to that of amine except the presence of the hydroxyl group. In such a case, oxygen has a higher electronegativity than that of nitrogen, so alkanol compounds are more acidic in nature in comparison to the amines.
On account of the ability to form hydrogen bonds, the amines have tendencies of high solubility in water. The amine molecules such as Ethyl, diethyl, triethyl, and Methyl are gaseous in nature. Whereas, higher weight amines have a solid structure and alkyl amines have a liquid structure. There is an ammonia smell to gaseous amines and a fishy smell to liquid amines. The solubility of amines entirely depends upon the number of carbon atoms in the molecule.