Step 1: Investigate symmetry properties.
Let \( A \) be a symmetric matrix, i.e., \( A = A' \), and let \( B \) be any matrix.
Now, consider the expression:
\[
(B'AB)' = B'A'B' = B'AB.
\]
This shows that \( B'AB \) is symmetric if \( A \) is symmetric.
Step 2: Investigate skew-symmetry.
If \( A \) is skew-symmetric, i.e., \( A = -A' \):
\[
(B'AB)' = B'A'B = B'(-A)B = -B'AB.
\]
This indicates that \( B'AB \) cannot be skew-symmetric.
Final Answer:
\[
\boxed{\text{\( B'AB \) is symmetric if \( A \) is symmetric.}}
\]