When solving equations to identify empty sets, remember that if the equation leads to a condition that has no solution in the given set (in this case, real numbers), the set is empty.
The correct answer is: (D): \( \{ x : x^2 + 1 = 0, x \in \mathbb{R} \} \)
We are tasked with identifying which of the following sets is an empty set. Let’s analyze each option:
Step 1: Examine the set \( \{ x : x^2 + 1 = 0, x \in \mathbb{R} \} \)
This set contains all real numbers \( x \) that satisfy the equation \( x^2 + 1 = 0 \). Let’s solve this equation:
There is no real number \( x \) whose square is negative. Therefore, there are no solutions to the equation \( x^2 + 1 = 0 \) in the set of real numbers \( \mathbb{R} \). This implies that the set is empty.
Step 2: Conclusion
Since no real number satisfies the given equation, the set \( \{ x : x^2 + 1 = 0, x \in \mathbb{R} \} \) is indeed an empty set.
Conclusion:
The correct answer is (D): \( \{ x : x^2 + 1 = 0, x \in \mathbb{R} \} \), as it is the empty set.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: