Question:

Which of the following is a subgroup of the group $G = \{1, 2, 3, 4, 5, 6\}$ under $\otimes_7$ ?

Updated On: May 11, 2024
  • $\{2, 6, 1\}$
  • $\{1, 2, 4\}$
  • $\{5, 4, 2\}$
  • $\{2, 3 , 1\}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

$G = \{1, 2, 3, 4, 5, 6\}, \oplus_7$
(a) $\{2, 6, 1) $ is not a subgroup
$\because 2\oplus_7 6=5 \notin \{ 2,6, 1 \}$
(b) $\{1, 2, 4\}$ is a subgroup
$\because$ it satisfies all properties of group.

$ 1\oplus_7 2=2, 2 \oplus_7 4=1,4 \oplus_7 1=4$
(c) $ \{5, 4, 2 \}$ is not a subgroup ?
$\because $ In this set identity element do not exist.
(d) $ \{2, 3, 1\} $ is not a subgroup
$\because 2 \oplus_7 3 = 6 \notin \{2, 3, 1\}$
Was this answer helpful?
0
0

Concepts Used:

Relations and functions

A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.

A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.

Representation of Relation and Function

Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.

  1. Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
  2. Roster form - {(1, 1), (2, 4), (3, 9)}
  3. Arrow Representation