The boiling point of a substance depends on its molecular interactions. The stronger the intermolecular forces (such as hydrogen bonding), the higher the boiling point. Let's analyze each option:
1. HCOOH (Formic acid): Formic acid has strong hydrogen bonding due to the presence of both a hydroxyl group (-OH) and a carbonyl group (C=O), leading to a high boiling point.
2. CH\(_3\)CH\(_2\)OH (Ethanol): Ethanol also has strong hydrogen bonding due to the hydroxyl group (-OH), resulting in a relatively high boiling point.
3. CH\(_3\)CH\(_2\)NH\(_2\) (Ethanamine): Ethanamine contains an amine group (-NH\(_2\)) which can form hydrogen bonds, but the hydrogen bonding in amines is generally weaker than in alcohols and acids. Thus, it has a lower boiling point compared to the previous two compounds.
4. CH\(_3\)OCH\(_3\) (Dimethyl ether): Dimethyl ether has weaker London dispersion forces and no hydrogen bonding compared to the alcohols and acids. Therefore, it has the lowest boiling point.
Thus, CH\(_3\)CH\(_2\)NH\(_2\) has the lowest boiling point among the options.
Therefore, the correct answer is (C) CH\(_3\)CH\(_2\)NH\(_2\).
To determine which compound has the lowest boiling point, we need to consider the types of intermolecular forces present in each compound:
1. HCOOH (Formic Acid): Formic acid has strong hydrogen bonding between molecules due to the presence of both an -OH group and a -C=O group. This results in a relatively high boiling point.
2. CH$_3$CH$_2$OH (Ethanol): Ethanol also exhibits hydrogen bonding due to the presence of the -OH group. The hydrogen bonds make ethanol’s boiling point relatively high, but lower than formic acid’s.
3. CH$_3$CH$_2$NH$_2$ (Ethanamine): Ethanamine has hydrogen bonding but not as strong as alcohols or carboxylic acids because the nitrogen atom is less electronegative than oxygen, and the hydrogen bonding is not as effective. This results in a relatively lower boiling point.
4. CH$_3$OCH$_3$ (Dimethyl Ether): Dimethyl ether has weak dipole-dipole interactions and London dispersion forces but lacks hydrogen bonding. This results in a much lower boiling point compared to the other compounds.
Thus, CH$_3$CH$_2$NH$_2$ (ethanamine) has the lowest boiling point because it has weaker intermolecular forces (hydrogen bonding is weaker than in alcohols and acids), making it the correct answer.
Replacement of a hydrogen atom in a hydrocarbon by an alkoxy or carboxyl group yields a class of compounds known as ethers. Ethers are classified as symmetrical or unsymmetrical on the basis of groups attached to the oxygen atoms. Diethyl ether, a symmetrical ether, has been widely used as an inhalation anesthetic. Ethers can be prepared by acid catalyzed intermolecular dehydration of alcohols and Williamson's synthesis. Acid catalyzed dehydration of alcohols is not generally preferred as it gives a mixture of elimination and substitution products. In Williamson's synthesis, an alkyl halide is allowed to react with sodium alkoxide. Ethers containing substituted Alkyl groups may also be prepared by this method. The C-O bond in ether is weakly polar and is cleaved under drastic conditions with excess of hydrogen halides. In electrophilic substitution, the alkoxy group deactivates the aromatic ring and directs the incoming group to ortho and para positions.
IUPAC name of the given ether is:
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
For x < 0:
f(x) = ex + ax
For x ≥ 0:
f(x) = b(x - 1)2
A class of organic compounds that mostly contain an ether group in which the oxygen atom is bonded to two alkyl or aryl groups are referred to as Ethers. For the same, C-O-C is the functional group.
Ethers are less polar as well as less reactive, and they do not react with active metals (Na, K), cold dilute acid, oxidizing and reducing agents or other chemicals.
The reason is that they do not have an active functional group.