For ether synthesis, the alkoxide anion attacks the alkyl halide in an \(\text{S}_\text{N}\)2 reaction mechanism to form the ether. In this case, using ethyl iodide (\(\text{CH}_3\text{CH}_2\text{Br}\)) with a strong base such as sodium ethoxide (\(\text{CH}_3\text{CH}_2\text{ONa}\)) can generate ethers efficiently. The second pair involves a reaction with bromine to form the desired ethers.