Question

Which of the following expression is correct?

• A. $\Delta G = -RT \ln K$
• B. $\Delta G = \dfrac{1}{RT^2} \ln K$
• C. $\Delta G^\circ = -RT \ln K$
• D. $\Delta G^\circ = -\dfrac{1}{RT^2} \ln K$

Hint:

Remember: $\Delta G^\circ = -RT \ln K$ links thermodynamics with equilibrium.

Answer 1

The Correct Option is C

The standard Gibbs free energy change is related to the equilibrium constant as:
$\Delta G^\circ = -RT \ln K$