Question

Which of the following compounds undergoes Markovnikov addition when treated with HBr?

• A. CH2=CH2
• B. CH3-CH=CH2
• C. CH3-C=CH
• D. CH-CH2

Hint:

Markovnikov's rule is applicable to unsymmetrical alkenes, where the more substituted carbon will attract the halogen.

Answer 1

The Correct Option is B

Markovnikov's rule states that when HX is added to an alkene, the hydrogen atom attaches to the carbon atom that already has the greater number of hydrogen atoms (the more substituted carbon atom). In the compound \( \text{CH}_3\text{-CH}=\text{CH}_2 \), the hydrogen from HBr will add to the carbon atom in the double bond that has more hydrogen atoms (the CH2 group), and the bromine will add to the more substituted carbon (the CH3 group). Thus, the compound that follows Markovnikov's rule is \( \text{CH}_3\text{-CH}=\text{CH}_2 \).
Final answer
Answer: \(\boxed{\text{CH}_3\text{-CH}=\text{CH}_2}\)