Which of the following compound can give positive iodoform test when treated with aqueous KOH solution followed by potassium hypoiodite.
The Correct Option is B
Approach Solution - 1
The iodoform test is a chemical reaction used to identify the presence of methyl ketones (a ketone with a methyl group, \(-COCH_3\)) or specific alcohols that can be oxidized to methyl ketones. The reaction involves the compound being treated with aqueous potassium hydroxide (KOH) followed by potassium hypoiodite (KI/I2 solution).
To determine which compound among the given options can give a positive iodoform test, we need to check for the presence of the \(-COCH_3\) group or an alcohol that can be oxidized to it.
- Examine each compound:
- Compound 1: Does not have the \(-COCH_3\) group or an alcohol group that can be oxidized to give it.
- Compound 2: Contains a methyl ketone group (\(-COCH_3\)), which fits the criteria for the iodoform test.
- Compound 3: Does not have the \(-COCH_3\) group and cannot be oxidized to form one.
- Compound 4: Also lacks the \(-COCH_3\) group and cannot be easily oxidized to form one.
- Thus, Compound 2 is the only one that can give a positive iodoform test because it contains the necessary methyl ketone group.
Thus, the correct answer is Compound 2
Approach Solution -2
The correct answer is (2)
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