Question:

Which of the following compound can give positive iodoform test when treated with aqueous KOH solution followed by potassium hypoiodite.

Updated On: Nov 3, 2025
  • Compound 1
  • Compound 2
  • Compound 3
  • Compound 4
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The Correct Option is B

Approach Solution - 1

The iodoform test is a chemical reaction used to identify the presence of methyl ketones (a ketone with a methyl group, \(-COCH_3\)) or specific alcohols that can be oxidized to methyl ketones. The reaction involves the compound being treated with aqueous potassium hydroxide (KOH) followed by potassium hypoiodite (KI/I2 solution).

To determine which compound among the given options can give a positive iodoform test, we need to check for the presence of the \(-COCH_3\) group or an alcohol that can be oxidized to it.

  1. Examine each compound:
    • Compound 1: Does not have the \(-COCH_3\) group or an alcohol group that can be oxidized to give it.
    • Compound 2: Contains a methyl ketone group (\(-COCH_3\)), which fits the criteria for the iodoform test.
    • Compound 3: Does not have the \(-COCH_3\) group and cannot be oxidized to form one.
    • Compound 4: Also lacks the \(-COCH_3\) group and cannot be easily oxidized to form one.
  2. Thus, Compound 2 is the only one that can give a positive iodoform test because it contains the necessary methyl ketone group.

Thus, the correct answer is Compound 2

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Approach Solution -2

Solution 71
The correct answer is (2)

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