Question:

Which of the following choices represents \(^{239}_{94}Pu\) producing a positron?

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Positron emission decreases the atomic number by 1 while keeping the mass number the same.
Updated On: Apr 1, 2025
  • \(^{239}_{94}Pu \rightarrow ^{235}_{94}Pu + ^{4}_2He\)
  • \(^{239}_{94}Pu \rightarrow e^- + ^{239}_{93}Np\)
  • \(^{239}_{94}Pu \rightarrow \sigma^-1 + ^{239}_{94}Np\)
  • \(^{239}_{94}Pu \rightarrow ^{239}_{93}Np + e^+\)
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The Correct Option is D

Solution and Explanation

Positron emission occurs when a proton in the nucleus decays to form a neutron, releasing a positron in the process. Therefore, the correct nuclear reaction is \(^{239}_{94}Pu \rightarrow ^{239}_{93}Np + e^+\). Thus, the correct answer is (d).
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