To solve the problem, we need to identify which type of matrix can be both symmetric and skew-symmetric.
1. Understanding Symmetric and Skew-Symmetric Matrices:
A matrix \( A \) is symmetric if:
\( A^T = A \)
A matrix \( A \) is skew-symmetric if:
\( A^T = -A \)
Now, if a matrix is both symmetric and skew-symmetric, then:
\( A = A^T = -A \Rightarrow A = -A \)
This implies:
\( 2A = 0 \Rightarrow A = 0 \)
So, the only matrix that satisfies both conditions is the null matrix (all elements are zero).
2. Evaluating Each Option:
(A) Unit Matrix → Not possible. It's symmetric but not skew-symmetric.
(B) Diagonal Matrix → Could be symmetric, but not necessarily skew-symmetric.
(C) Null Matrix → Satisfies both \( A = A^T \) and \( A = -A \). → Correct
(D) Row Matrix → Not necessarily square, and thus not even eligible for symmetric/skew-symmetric.
3. Conclusion:
The null matrix is the only matrix that is both symmetric and skew-symmetric.
Final Answer:
The correct answer is Null Matrix.
An amount of ₹ 10,000 is put into three investments at the rate of 10%, 12% and 15% per annum. The combined annual income of all three investments is ₹ 1,310, however, the combined annual income of the first and second investments is ₹ 190 short of the income from the third. Use matrix method and find the investment amount in each at the beginning of the year.
If \[ A = \begin{bmatrix} 1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1 \end{bmatrix} \] then find \( A^{-1} \). Hence, solve the system of linear equations: \[ x - 2y = 10, \] \[ 2x - y - z = 8, \] \[ -2y + z = 7. \]