In an \( S_N1 \) reaction, the leaving group must depart easily, and the carbocation formed must be stable. Among the halides, \( \text{I}^
\) is the best leaving group, followed by \( \text{Br}^
\), \( \text{Cl}^
\), and \( \text{F}^
\). Since \( \text{I}^
\) is the best leaving group, the alkyl halide with \( \text{I} \) will undergo \( S_N1 \) reactions most readily.
Final Answer: The alkyl halide \( (\text{CH}_3)_3 \text{C} \, \text{I} \) will undergo the \( S_N1 \) reaction most readily.