The isomer of C4H9Cl with the lowest boiling point is tert-butyl chloride (C4H9Cl), also known as 2-chloro-2-methylpropane (CH3)3C-Cl.
This is because the high degree of branching in the tert-butyl chloride molecule reduces the surface area available for intermolecular interactions, such as Van der Waals forces. With fewer opportunities for these interactions, the molecule is easier to vaporize, leading to a lower boiling point compared to less branched isomers, such as n-butyl chloride or sec-butyl chloride.
Choose the correct sets with respective observations:
(1) \( \text{CuSO}_4 \) (acidified with acetic acid) + \( K_2\text{Fe(CN)}_6 \) (neutralized with NaOH) → Blue precipitate
(2) \( 2\text{CuSO}_4 \) + \( K_2\text{Fe(CN)}_6 \) → Blue precipitate
(3) \( 4\text{FeCl}_3 \) + \( 3\text{K}_4\text{Fe(CN)}_6 \) → \( \frac{1}{2}K_4\text{Fe(CN)}_6 \)
(4) \( 37\text{Cl}_2 \) + \( 2\text{KFe(CN)}_6 \) → 6KC1
In the light of the above options, choose the correct set:
Given below are two statements:
Statement (I): In octahedral complexes, when \( \Delta_o < P \) high spin complexes are formed. When \( \Delta_o > P \) low spin complexes are formed.
Statement (II): In tetrahedral complexes because of \( \Delta_t < P \), low spin complexes are rarely formed.
In the light of the above statements, choose the most appropriate answer from the options given below: