To solve this problem, we need to identify the suitable reagent for the given conversion.
1. Understanding the Reaction:
The reaction involves the oxidation of a compound with an alkene group (CH₃-CH=CH-CH₂-COCH₃). The product shows a carboxylic acid group (-COOH) on the terminal carbon. This suggests that the compound undergoes oxidation at the position of the alkene group (double bond), converting it to a carboxyl group.
2. Analyzing the Reagents:
Let's evaluate the possible reagents that could effect this transformation:
Final Answer:
The most suitable reagent for this conversion is (C) "I₂ and NaOH solution with subsequent acidification," as it is used for the oxidative cleavage of alkenes to form carboxylic acids.
The given reaction involves the conversion of an α,β-unsaturated carbonyl compound (CH3CH=CHCOCH3) into a β-hydroxy ketone (CH3CH=CHCOOH) through an aldol-like reaction. This type of conversion is a typical reaction of an enone with iodine in an alkaline medium, followed by acidification. This is known as the iodoform test or iodine in alkaline solution, which results in the formation of a β-hydroxy ketone and the release of iodine in the process.
The mechanism involves the formation of an enolate ion under the basic conditions provided by NaOH, which then reacts with I2 to form the desired product.
The correct answer is (C) : I2 and NaOH solution with subsequent acidification.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: