(i) \(\frac{2}{3}\), \(\frac{5}{2}\)
By converting these into like fractions,
\(\frac{2}{3}\) = \(\frac{2\times 2}{3\times 2}\)= 4/6
\(\frac{5}{2}\)= \(\frac{5\times 3}{2\times 3}\) =\(\frac{15}{6}\)
As 15 > 4, therefore, \(\frac{5}{2}\) is greater.
(ii) -\(\frac{5}{6}\), -\(\frac{4}{3}\)
-\(\frac{4}{3}\) = -\(\frac{4\times 2}{3\times 2}\) = -\(\frac{8}{6}\)
As -5>-8, therefore, -\(\frac{5}{6}\) is greater.
Match the items given in Column I with one or more items of Column II.
Column I | Column II |
(a) A plane mirror | (i) Used as a magnifying glass. |
(b) A convex mirror | (ii) Can form image of objects spread over a large area. |
(c) A convex lens | (iii) Used by dentists to see enlarged image of teeth. |
(d) A concave mirror | (iv) The image is always inverted and magnified. |
(e) A concave lens | (v) The image is erect and of the same size as the object. |
- | (vi) The image is erect and smaller in size than the object. |