(i) \(\frac{2}{3}\), \(\frac{5}{2}\)
By converting these into like fractions,
\(\frac{2}{3}\) = \(\frac{2\times 2}{3\times 2}\)= 4/6
\(\frac{5}{2}\)= \(\frac{5\times 3}{2\times 3}\) =\(\frac{15}{6}\)
As 15 > 4, therefore, \(\frac{5}{2}\) is greater.
(ii) -\(\frac{5}{6}\), -\(\frac{4}{3}\)
-\(\frac{4}{3}\) = -\(\frac{4\times 2}{3\times 2}\) = -\(\frac{8}{6}\)
As -5>-8, therefore, -\(\frac{5}{6}\) is greater.