Question

Fill in the boxes with the correct symbol out of >, <, and =.
(i) -\(\frac{5}{7}\)__ \(\frac{2}{3}\) (ii) -\(\frac{4}{5}\)__-\(\frac{5}{7}\) (iii) -\(\frac{7}{8}\) __\(\frac{14}{-16}\) (iv) \(\frac{-8}{5}\) __\(\frac{-7}{4}\)(v) \(\frac{1}{-3}\) __\(\frac{-1}{4}\) (vi)\(\frac{5}{-11}\) __\(\frac{-5}{11}\) (vii) 0__ \(\frac{-7}{6}\)

Answer 1

(i) -\(\frac{5}{7}\)__ \(\frac{2}{3}\) 
\(-\frac{5}{7}\) = \(\frac{-5\times 3}{7\times 3}\) = \(\frac{-15}{21}\)
\(\frac{2}{3}\) = \(\frac{2\times7}{3\times 7}\) =\(\frac{14}{21}\)
As - 15 < 14, 
Therefore, -\(\frac{5}{7}\)<\(\frac{2}{3}\)

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(ii)-\(\frac{4}{5}\)__-\(\frac{5}{7}\)
-\(\frac{4}{5}\) = -\(\frac{4\times7}{5\times 7}\) = \(-\frac{28}{35}\)
\(-\frac{5}{7}\) = \(-\frac{5\times5}{5\times 7}\) =\(-\frac{25}{35}\)
As - 28 < - 25
Therefore, \(-\frac{4}{5}\) < \(-\frac{5}{7}\)