Find :
(i)\(\frac{7}{24}\)-\(\frac{17}{36}\)
(ii) \(\frac{5}{63}\)-(\(-\frac{6}{21}\))
(iii) -\(\frac{6}{13}\)-(-\(\frac{7}{15}\))
(iv) -\(\frac{3}{8}\)-\(\frac{7}{11}\)
(v)\(-\frac{21}{9}\)-6
(i)\(\frac{7}{24}\)-\(\frac{17}{36}\)
(ii) \(\frac{5}{63}\)-(\(-\frac{6}{21}\))
(iii) -\(\frac{6}{13}\)-(-\(\frac{7}{15}\))
(iv) -\(\frac{3}{8}\)-\(\frac{7}{11}\)
(v)\(-\frac{21}{9}\)-6
Solution and Explanation
(i) \(\frac{7}{24}\)-\(\frac{17}{36}\)
L.C.M of 24 and 36 is 72.
\(\frac{7}{24}\)-\(\frac{17}{36}\) = \(\frac{7\times3}{24\times3}-\frac{17\times2}{36\times2}\) = \(\frac{21}{72}\)= -\(\frac{13}{72}\)
(ii) \(\frac{5}{63}\)-(\(-\frac{6}{21}\))
= \(\frac{5}{63}+\frac{2}{7}\)
= L.C.M of 63 and 7 is 63.
\(\frac{5}{63}+\frac{2}{7}\)= \(\frac{5}{63}+\frac{18}{63}\) =\(\frac{5+18}{63}\) = \(\frac{23}{63}\)
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