(i) \(\frac{7}{24}\)-\(\frac{17}{36}\)
L.C.M of 24 and 36 is 72.
\(\frac{7}{24}\)-\(\frac{17}{36}\) = \(\frac{7\times3}{24\times3}-\frac{17\times2}{36\times2}\) = \(\frac{21}{72}\)= -\(\frac{13}{72}\)
(ii) \(\frac{5}{63}\)-(\(-\frac{6}{21}\))
= \(\frac{5}{63}+\frac{2}{7}\)
= L.C.M of 63 and 7 is 63.
\(\frac{5}{63}+\frac{2}{7}\)= \(\frac{5}{63}+\frac{18}{63}\) =\(\frac{5+18}{63}\) = \(\frac{23}{63}\)
Give first the step you will use to separate the variable and then solve the equation:
(a) x – 1 = 0
(b) x + 1 = 0
(c) x – 1 = 5
(d) x + 6 = 2
(e) y – 4 = – 7
(f) y – 4 = 4
(g) y + 4 = 4
(h) y + 4 = – 4