>
Exams
>
Chemistry
>
Oxides
>
which is amphoteric
Question:
Which is amphoteric :
JIPMER MBBS - 2018
JIPMER MBBS
Updated On:
Jun 21, 2024
Al
2
O
3
CrO
3
BeO
CO
2
Hide Solution
Verified By Collegedunia
The Correct Option is
A
Solution and Explanation
The correct option is (A): Al
2
O
3
.
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Oxides
Oxides of aluminium and zinc are :
CBSE Class X - 2024
Science
Oxides
View Solution
Among
CrO
\text{CrO}
CrO
,
Cr
2
O
3
\text{Cr}_2\text{O}_3
Cr
2
O
3
, and
CrO
3
\text{CrO}_3
CrO
3
, the sum of spin-only magnetic moment values of basic and amphoteric oxides is ______
×
1
0
−
2
BM
\times 10^{-2} \, \text{BM}
×
1
0
−
2
BM
(nearest integer).
Given:
Atomic number of Cr is 24.
JEE Main - 2024
Chemistry
Oxides
View Solution
Among the following oxides of p-block elements, the number of oxides having amphoteric nature is:
Cl
2
O
7
,
CO
,
PbO
2
,
N
2
O
,
NO
,
Al
2
O
3
,
SiO
2
,
N
2
O
5
,
SnO
2
\text{Cl}_2\text{O}_7, \, \text{CO}, \, \text{PbO}_2, \, \text{N}_2\text{O}, \, \text{NO}, \, \text{Al}_2\text{O}_3, \, \text{SiO}_2, \, \text{N}_2\text{O}_5, \, \text{SnO}_2
Cl
2
O
7
,
CO
,
PbO
2
,
N
2
O
,
NO
,
Al
2
O
3
,
SiO
2
,
N
2
O
5
,
SnO
2
JEE Main - 2024
Chemistry
Oxides
View Solution
Arrange the following oxoacids of phosphorus in the correct decreasing order of their reducing strength.
A. H
4
P
2
O6
B. H
3
PO
2
C. H
4
P
2
O
7
D. H
3
PO
3
Choose the correct answer from the options given below :
CUET (UG) - 2023
Chemistry
Oxides
View Solution
Zinc oxide is white in colour at room temperature. It appears yellow on heating because of :
CUET (UG) - 2023
Chemistry
Oxides
View Solution
View More Questions
Questions Asked in JIPMER MBBS exam
If same charge q is placed inside a sphere and cube having radius 1m and side 2m respectively. What will be the ratio of flux passing through them ?
JIPMER MBBS - 2019
Electric Flux
View Solution
B
r
O
3
−
BrO^{3-}
B
r
O
3
−
Changes into
B
r
2
Br_2
B
r
2
in an acidic medium of a unbalanced equation how many electron should be present on the balanced electron.
JIPMER MBBS - 2019
Balancing a redox reaction
View Solution
If resistivity of copper is
1.72
×
1
0
−
8
Ω
−
m
1.72×10^{-8} \Omega-m
1.72
×
1
0
−
8
Ω
−
m
and number of free electron in copper is
8.5
×
1
0
28
/
m
3
8.5×10^{28} / m^3
8.5
×
1
0
28
/
m
3
. Find mobility
JIPMER MBBS - 2019
Resistance and Resistivity
View Solution
If equilibrium constant is 2.6×10
8
then find the value of ΔG°.
JIPMER MBBS - 2019
Thermodynamics
View Solution
Level of LH is maximum :
JIPMER MBBS - 2019
Hormones
View Solution
View More Questions