Which factors are required for the success of democracy in India ?
Show Hint
Solution and Explanation
Correct Answer: Factors required for the success of democracy in India.
Step 1: Active Citizen Participation
Beyond voting, citizens should stay informed, deliberate on public issues, volunteer, and hold representatives accountable. Participation keeps democracy vibrant and responsive.
Step 2: Awareness of Rights and Duties
Knowing fundamental rights (speech, equality, vote) and observing civic duties (lawfulness, respect for others’ rights, public spirit) creates a culture that sustains democratic institutions.
Step 3: Strong and Accountable Leadership
Effective governance with transparency, integrity, and answerability builds public trust and curbs corruption or abuse of power.
Step 4: Rule of Law and Equality Before Law
Uniform application of laws to all — including those in authority — ensures justice, rights protection, and fair dispute resolution.
Step 5: Freedom of Press and Independent Judiciary
A free press informs citizens and scrutinizes power; an independent judiciary safeguards rights and checks executive/legislative excesses. Together, they uphold accountability and constitutionalism.
Step 6: Tolerance and Respect for Diversity
India’s plural society requires embracing religious, linguistic, cultural diversity. Tolerance reduces conflict and ensures inclusive representation.
\[ \textbf{Summary: }\; \text{Participation} + \text{Rights \& Duties} + \text{Accountable Leadership} + \text{Rule of Law} + \text{Free Press/Judiciary} + \text{Respect for Diversity}. \]
Top Questions on Civics
Questions Asked in Maharashtra Class X Board exam
Complete the following activity to prove that the sum of squares of diagonals of a rhombus is equal to the sum of the squares of the sides.
Given: PQRS is a rhombus. Diagonals PR and SQ intersect each other at point T.
To prove: PS\(^2\) + SR\(^2\) + QR\(^2\) + PQ\(^2\) = PR\(^2\) + QS\(^2\)
Activity: Diagonals of a rhombus bisect each other.
In \(\triangle\)PQS, PT is the median and in \(\triangle\)QRS, RT is the median.
\(\therefore\) by Apollonius theorem,
\[\begin{aligned} PQ^2 + PS^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(I)} \\ QR^2 + SR^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(II)} \\ \text{Adding (I) and (II),} \quad PQ^2 + PS^2 + QR^2 + SR^2 &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \\ &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \quad (\text{RT = PT}) \\ &= 4PT^2 + 4QT^2 \\ &= (\boxed{\phantom{X}})^2 + (2QT)^2 \\ \therefore \quad PQ^2 + PS^2 + QR^2 + SR^2 &= PR^2 + \boxed{\phantom{X}} \\ \end{aligned}\]
- Maharashtra Class X Board - 2025
- Quadrilaterals
- Prove that tangent segments drawn from an external point to a circle are congruent.
- Draw a circle with radius 4.1 cm. Construct tangents to the circle from a point at a distance 7.3 cm from the centre.
- Maharashtra Class X Board - 2025
- Constructions
- \(\triangle\)ABC \(\sim\) \(\triangle\)PQR. In \(\triangle\)ABC, AB = 3.6 cm, BC = 4 cm and AC = 4.2 cm. The corresponding sides of \(\triangle\)ABC and \(\triangle\)PQR are in the ratio 2 : 3, construct \(\triangle\)ABC and \(\triangle\)PQR.
- Maharashtra Class X Board - 2025
- Constructions
- \(\square\)ABCD is a rectangle. Taking AD as a diameter, a semicircle AXD is drawn which intersects the diagonal BD at X. If AB = 12 cm, AD = 9 cm, then find the values of BD and BX.