Question:

Which among the following observations suggests that glucose also exists in cyclic form?

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Absence of typical aldehyde reactions in glucose indicates its cyclic hemiacetal structure.
Updated On: Feb 4, 2026
  • Acetylation of glucose obtains glucose penta acetate.
  • Glucose does not undergo condensation with 2,4-dinitrophenylhydrazine.
  • Prolong heating of glucose with HI yields n-hexane.
  • Hydroxylamine reacts with glucose to form glucose oxime.
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The Correct Option is B

Solution and Explanation

Step 1: Expected behaviour of aldehydes.
Open-chain glucose contains an aldehyde group ($-CHO$), which should react with 2,4-dinitrophenylhydrazine to form a hydrazone.
Step 2: Actual observation.
Glucose does not give the 2,4-DNP test, indicating the absence of a free aldehyde group in its predominant form.
Step 3: Reason for this behaviour.
The aldehyde group of glucose reacts intramolecularly with a hydroxyl group to form a hemiacetal ring structure, resulting in a cyclic form of glucose.
Step 4: Conclusion.
The failure of glucose to react with 2,4-dinitrophenylhydrazine confirms that glucose mainly exists in a cyclic form.
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