Question

Match List-I with List-II.

Choose the correct answer from the options given below:

• A. A-IV, B-I, C-II, D-III
• B. A-IV, B-III, C-II, D-I
• C. A-I, B-III, C-IV, D-II
• D. A-III, B-I, C-IV, D-II

Hint:

Different reagents oxidise or derivatise different functional groups of glucose, leading to distinct characteristic products.

Answer 1

The Correct Option is A

Step 1: Analyse each reaction of glucose.
Reaction with hydroxylamine: Glucose reacts with hydroxylamine to form an oxime, known as glucoxime. Hence, \[ \text{A} \rightarrow \text{IV} \]
Reaction with bromine water: Bromine water is a mild oxidising agent and oxidises the aldehyde group of glucose to form gluconic acid. Hence, \[ \text{B} \rightarrow \text{I} \]
Reaction with excess acetic anhydride: All five hydroxyl groups of glucose are acetylated, forming glucose pentaacetate. Hence, \[ \text{C} \rightarrow \text{II} \]
Reaction with concentrated nitric acid: Both aldehyde and primary alcohol groups are oxidised to carboxylic acids, forming saccharic acid. Hence, \[ \text{D} \rightarrow \text{III} \]

Step 2: Write the final matching.
\[ \text{A-IV,\; B-I,\; C-II,\; D-III} \]
Final Answer: \[ \boxed{\text{A-IV, B-I, C-II, D-III}} \]