Question:

When the input to Q is a 1 level, the frequency of oscillations of the timer circuit is _______.

 

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555 timer oscillation freq = \( \frac{1.44}{(R_A + 2R_B)C} \) in astable mode. Easy to memorize!
Updated On: Jun 24, 2025
  • \( \frac{1.44}{(R_A + 2R_B)C} \)
  • \( \frac{1.44}{(R_A + R_B)C} \)
  • \( \frac{1.44}{(2R_A + R_B)C} \)
  • \( \frac{1.44}{(R_B + 2R_A)C} \)
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The Correct Option is A

Solution and Explanation

Step 1: 555 Timer in Astable Mode
In astable mode, the 555 timer continuously oscillates. The frequency of oscillation is determined by two resistors and a capacitor.
Step 2: Formula for Frequency
\[ f = \frac{1.44}{(R_A + 2R_B)C} \] This formula arises due to:
- \( T_{high} = 0.693 (R_A + R_B)C \)
- \( T_{low} = 0.693 R_B C \)
Step 3: Calculate
\[ T = T_{high} + T_{low} = 0.693 (R_A + 2R_B)C \Rightarrow f = \frac{1.44}{(R_A + 2R_B)C} \] Conclusion:
Option (1) is correct — it’s the standard 555 timer frequency formula in astable mode.
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