The reaction involved is:
\[2\text{NH}_4\text{Cl} + \text{MnO}_2 + 2\text{H}_2\text{SO}_4 \xrightarrow{\Delta} \text{MnSO}_4 + (\text{NH}_4)_2\text{SO}_4 + 2\text{H}_2\text{O} + \text{Cl}_2 \uparrow\]
In this reaction, chlorine gas (\( \text{Cl}_2 \)) is liberated, which has a greenish-yellow color.
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)