When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters ?
- 1:02
- 2:01
- 4:01
- 1:04
The Correct Option is B
Solution and Explanation
$\Rightarrow \frac{W_1}{W_2} =\frac{?_2}{?_1}= \frac{600}{300}= 2$
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Concepts Used:
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Heisenberg’s Uncertainty Principle states that both the momentum and position of a particle cannot be determined simultaneously.