Question:
When initial concentration of the reactant is doubled, the half-life period of a zero order reaction
When initial concentration of the reactant is doubled, the half-life period of a zero order reaction
Updated On: May 21, 2024
- is halved
- is tripled
- is doubled
- remains unchanged
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The correct option is (C) :is doubled.
Was this answer helpful?
0
0
Top Questions on Order of Reaction
- A reaction is of second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is (i) doubled, (ii) reduced to half?
- CBSE CLASS XII - 2025
- Chemistry
- Order of Reaction
For a first-order reaction, the concentration of reactant was reduced from 0.03 mol L\(^{-1}\) to 0.02 mol L\(^{-1}\) in 25 min. What is its rate (in mol L\(^{-1}\) s\(^{-1}\))?
- AP EAPCET - 2024
- Chemistry
- Order of Reaction
- Consider the following reaction
\[A + B \rightarrow C\]
The time taken for A to become 1/4th of its initial concentration is twice the time taken to become 1/2 of the same. Also, when the change of concentration of B is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis.
The overall order of the reaction is ____.- JEE Main - 2024
- Chemistry
- Order of Reaction
- Consider the two different first-order reactions given below: \[\text{A + B} \rightarrow \text{C (Reaction 1)} \\\text{P} \rightarrow \text{Q (Reaction 2)}\]The ratio of the half-life of Reaction 1 : Reaction 2 is $5 : 2$. If $t_1$ and $t_2$ represent the time taken to complete $\frac{2}{3}^\text{rd}$ and $\frac{4}{5}^\text{th}$ of Reaction 1 and Reaction 2, respectively, then the value of the ratio $t_1 : t_2$ is ____ $\times 10^{-1}$ (nearest integer).[Given: $\log_{10}(3) = 0.477$ and $\log_{10}(5) = 0.699$]
- JEE Main - 2024
- Chemistry
- Order of Reaction
- The correct order of the number of unpaired electrons in the given complexes is
A. \([Fe(CN)_6]^{3–}\)
B. \([FeF_6]^{3–}\)
C. \([CoF_6]^{3–}\)
D. \([Cr(oxalate)_3]^{3–}\)
E. \([Ni(CO)_4]\)
Choose the correct answer from the options given below:- JEE Main - 2023
- Chemistry
- Order of Reaction
View More Questions
Questions Asked in NEET exam
- Match List I with List II
List-I
(Conversion)List-II
(Shape/geometry)(A) 1 mol of H2O to O2 (I) 3F (B) 1 mol of MnO-4 to Mn2+ (II) 2F (C) 1.5 mol of Ca from molten CaCl2 (III) 1F (D) 1 mol of FeO to Fe2O3 (IV) 5F
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Organic Chemistry- Some Basic Principles and Techniques
- Given below are two statements :
Statement I : Bone marrow is the main lymphoid organ where all blood cells including lymphocytes are produced.
Statement II : Both bone marrow and thymus provide micro environments for the development and maturation of T-lymphocytes.
In the light of above statements, choose the most appropriate answer from the options given below :- NEET (UG) - 2024
- Organ And Organ System
- The type of conservation in which the threatened species are taken out from their natural habitat and placed in special setting where they can be protected and given special care is called;
- NEET (UG) - 2024
- Biodiversity
- Given below are two statements:
Statement I: In C3 plants, some O2 binds to RuBisCO, hence CO, fixation is decreased.
Statement II: In C4 plants, mesophyll cells show very little photorespiration while bundle sheath cells do not show photorespiration.
In the light of the above statements, choose the correct answer from the options given below:- NEET (UG) - 2024
- respiration in plants
- Given below are two statements :
Statement I : In the nephron, the descending limb of loop of Henle is impermeable to water and permeable to electrolytes.
Statement II : The proximal convoluted tubule is lined by simple columnar brush border epithelium and increases the surface area for reabsorption.
In the light of the above statements, choose the correct answer from the option given below :- NEET (UG) - 2024
- Nephrons
View More Questions