Question

When heat is supplied to the gas in an isochoric process, the supplied heat changes its:

• A. Volume only
• B. Internal energy and volume
• C. Internal energy only
• D. Internal energy and temperature
• E. Temperature only

Hint:

In an isochoric process, since the volume is constant, the heat supplied only increases the internal energy, which causes an increase in temperature. No work is done in this process.

Answer 1

The Correct Option is D

In an isochoric process, the volume of the gas remains constant, which means that no work is done by the gas. 
The first law of thermodynamics states: \[ Q = \Delta U + W \] 
where \( Q \) is the heat supplied, \( \Delta U \) is the change in internal energy, and \( W \) is the work done by the gas. 
Since the volume is constant, \( W = 0 \). Therefore, the supplied heat \( Q \) is entirely used to change the internal energy \( \Delta U \) of the gas, which in turn results in a change in the temperature of the gas, because internal energy is related to temperature in the case of an ideal gas.
Thus, in an isochoric process, the supplied heat increases both the internal energy and temperature of the gas.
Thus, the correct answer is option (D), internal energy and temperature.