Question:

When HCl is treated with propane in presence of sodium peroxide, the major product obtained is

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In free radical substitution reactions, the primary carbon is usually the site of attack, leading to the formation of 1-chloropropane in this case.
Updated On: Jan 26, 2026
  • 1-Chloropropane
  • 1, 2-dichloropropane
  • 2-Chloropropane
  • 2, 2-dichloropropane
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the reaction with HCl and propane.
When HCl reacts with propane in the presence of sodium peroxide (Na\(_2\)O\(_2\)), a free radical substitution reaction occurs, leading to the formation of alkyl chlorides. The major product in this case is 1-chloropropane due to the primary carbon atom being more susceptible to radical attack.
Step 2: Analyzing the options.
(A) 1-Chloropropane: This is correct. The reaction leads to the formation of 1-chloropropane.
(B) 1, 2-dichloropropane: This is incorrect. The major product is not a dihalide.
(C) 2-Chloropropane: This is incorrect. The reaction preferentially forms 1-chloropropane, not 2-chloropropane.
(D) 2, 2-dichloropropane: This is incorrect. The reaction does not lead to a double chlorination at the same carbon atom.
Step 3: Conclusion.
The correct answer is (A) 1-Chloropropane.
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