Step 1: Understanding the reaction with HCl and propane.
When HCl reacts with propane in the presence of sodium peroxide (Na\(_2\)O\(_2\)), a free radical substitution reaction occurs, leading to the formation of alkyl chlorides. The major product in this case is 1-chloropropane due to the primary carbon atom being more susceptible to radical attack.
Step 2: Analyzing the options.
(A) 1-Chloropropane: This is correct. The reaction leads to the formation of 1-chloropropane.
(B) 1, 2-dichloropropane: This is incorrect. The major product is not a dihalide.
(C) 2-Chloropropane: This is incorrect. The reaction preferentially forms 1-chloropropane, not 2-chloropropane.
(D) 2, 2-dichloropropane: This is incorrect. The reaction does not lead to a double chlorination at the same carbon atom.
Step 3: Conclusion.
The correct answer is (A) 1-Chloropropane.