Question:
When excess of carbon dioxide is passed through lime water, the milkiness first formed disappears due to
When excess of carbon dioxide is passed through lime water, the milkiness first formed disappears due to
Updated On: Jul 7, 2022
- the reversible reaction taking place
- formation of water soluble calcium bicarbonate
- huge amount of heat evolved during the reaction
- formation of water soluble complex of calcium
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
When excess of carbon dioxide is passed in lime water, calcium carbonate is converted to calcium bicarbonate which is soluble, hence the milkiness due to calcium carbonate disappears.
$Ca(OH)_{2} +CO_{2} \to$ $\underset{\text{Milkiness}}{ {CaCO_{3}}}$ $?
$CaCO_{3} + H_{2}O +CO_{2} \to$$\underset{\text{soluble}}{ {Ca(HCO_{3})_{2}}}$
Was this answer helpful?
0
0
Top Questions on p -Block Elements
- $\textbf{Choose the correct statements about the hydrides of group 15 elements.}$
A. The stability of the hydrides decreases in the order \(\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3\)
B. The reducing ability of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
C. Among the hydrides, \(\text{NH}_3\) is a strong reducing agent while \(\text{BiH}_3\) is a mild reducing agent.
D. The basicity of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
Choose the most appropriate from the option given below:- JEE Main - 2024
- Chemistry
- p -Block Elements
- Identify the correct statements about p-block elements and their compounds.
(A) Non metals have higher electronegativity than metals.
(B) Non metals have lower ionisation enthalpy than metals.
(C) Compounds formed between highly reactive nonmetals and highly reactive metals are generally ionic.
(D) The non-metal oxides are generally basic in nature.
(E) The metal oxides are generally acidic or neutral in nature.- JEE Main - 2024
- Chemistry
- p -Block Elements
- $\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is:- JEE Main - 2024
- Chemistry
- p -Block Elements
The number of oxygen atoms present in chemical formula of fuming sulphuric acid is _______.
- JEE Main - 2024
- Chemistry
- p -Block Elements
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R
Assertion A: Helium is used to dilute oxygen in diving apparatus.
Reason R: Helium has high solubility in O2.
In the light of the above statements, choose the correct answer from the options given below.- NEET (UG) - 2023
- Chemistry
- p -Block Elements
View More Questions
Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family