When electric field is applied to the electrons in a conductor it starts
- When electric field is applied to the electrons in a conductor it starts
- Drifting from higher potential to lower potential
- Drifting from lower potential to higher potential
- Moving with constant velocity
The Correct Option is C
Solution and Explanation
The correct option is (C): Drifting from lower potential to higher potential
the electron starts drifting from the lower potential to higher potential.
drift velocity = \(v_d=-\frac{eE}{m}\tau\)
Top Questions on Electric Field
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Net dipole moment of a polar linear isotropic dielectric substance is not zero even in the absence of an external electric field. Reason
(R): In absence of an external electric field, the different permanent dipoles of a polar dielectric substance are oriented in random directions.
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Questions Asked in JEE Main exam
For a statistical data \( x_1, x_2, \dots, x_{10} \) of 10 values, a student obtained the mean as 5.5 and \[ \sum_{i=1}^{10} x_i^2 = 371. \] He later found that he had noted two values in the data incorrectly as 4 and 5, instead of the correct values 6 and 8, respectively.
The variance of the corrected data is:- JEE Main - 2025
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Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).