Question:
When current in a coil changes from 2 A to 5 A in a time of 0.3 s, if the emf induced in the coil is 40 mV, then the self-inductance of the coil is
When current in a coil changes from 2 A to 5 A in a time of 0.3 s, if the emf induced in the coil is 40 mV, then the self-inductance of the coil is
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For inductance problems, use the formula for induced emf and rearrange to solve for $L$.
Updated On: Jun 6, 2025
- 4 H
- 4 mH
- 40 mH
- 4 μH
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The Correct Option is B
Solution and Explanation
The emf induced in the coil is given by:
$$ \mathcal{E} = -L \frac{dI}{dt} $$
where $L$ is the inductance, and $\frac{dI}{dt}$ is the rate of change of current.
Substituting the given values, we can calculate the self-inductance $L$ to be 4 mH.
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