Question:

When an $\alpha$-particle is removed from $Ra$, the new element formed is of

Updated On: Jul 28, 2022
  • zero group
  • I st group
  • VII th group
  • III rd group
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The Correct Option is A

Solution and Explanation

$\underset{\text{Radium}}{_{88}Ra^{226}} \to \underset{\text{Radon}}{_{86}Rn^{222} }+ \,_{2} He^{4}$ Therefore, by removing a-particle from Radium, the new element formed is Radon which belongs to zero group.
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Concepts Used:

Group 18 Elements

The Group 18 elements, also known as noble gases except for Helium, are inert in nature because they have completely filled ns2 np6 electronic configuration in their valence shells. These gases also have high ionization enthalpy and more positive electron gain enthalpy. All these elements are chemically unreactive i.e. they don’t form many compounds.

Group 18 Elements consist of six elements. They are as mentioned below: 

  • Helium (He)
  • Neon (Ne)
  • Argon (Ar)
  • Krypton (Kr)
  • Xenon (Xe)
  • Radon (Rn)

Electronic Configuration:

The electronic configuration of Group 18 Elements along with their symbol and atomic number is given in the tabulated form below:

Trends in the Atomic Properties:

  • Atomic Radius: The nuclear radii increment on moving down the group with increasing nuclear number. This is a result of the expansion of another shell at each progressive element on moving down the group.
  • Electron Gain Enthalpy: Group 18 elements exhibit very stable electronic configurations. They do not have any tendency to accept an electron.
  • Ionisation Potential: They have high ionisation potentials, thanks to their closed electronic configurations. This value decreases on moving down the group due to an expansion in the nuclear size.