Question

The last element of the $p$-block in $6^{th}$ period is represented by the outer most electronic configuration

• A. $7s^2 7p^6$
• B. $5f^{14}6d^{10}7s^27p^5$
• C. $4f^{14}5d^{10}6s^26p^4$
• D. $4f^{14}5d^{10}6s^26p^6$

Answer 1

The Correct Option is D

The element with the electronic configuration 4$f^{14} 5d^{10} 6s^2 6p^4$ is the last element of the p-block in the 6th period, which corresponds to the element Lead (Pb). This configuration represents the completion of the 4f, 5d, and 6s subshells, with the last electron entering the 6p orbital, completing the p-block.

So, the correct answer is (D): $f^{14} 5d^{10} 6s^2 6p^4$