Question:

How many unpaired electrons are present in the element of atomic number 27 with a +2 oxidation state?

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For transition metals, the number of unpaired electrons can be found by looking at the electronic configuration of the ion.
Updated On: Jan 17, 2025
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The Correct Option is C

Solution and Explanation

The element with atomic number 27 is cobalt (Co). The electronic configuration of neutral Co is: \[ \text{Co}: [Ar] 3d^7 4s^2. \] In the +2 oxidation state, cobalt loses two electrons, which come from the 4s orbital, giving: \[ \text{Co}^{2+}: [Ar] 3d^7. \] The 3d subshell can accommodate 10 electrons, and the configuration of \( 3d^7 \) means there are 3 unpaired electrons.
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