Question:

When a wire is stretched to double its length:

Show Hint

For stretching problems: - Volume remains constant. - Use the relation \( r' = \frac{r}{\sqrt{\text{stretch ratio}}} \).
Updated On: Mar 26, 2025
  • Its radius is halved
  • Longitudinal strain is unity
  • Stress is equal to two times Young’s modulus
  • Young’s modulus is equal to thrice the energy per unit volume
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

When a wire is stretched, its volume remains constant. Let the initial length be \( L \) and radius \( r \), and after stretching, the new length is \( 2L \).
Since volume is conserved:
\[ \pi r^2 L = \pi r'^2 (2L) \] \[ r'^2 = \frac{r^2}{2} \] \[ r' = \frac{r}{\sqrt{2}} \] Since \( \sqrt{2} \approx 1.414 \), the radius is slightly more than half but approximately close.
Was this answer helpful?
0
0

Top Questions on Elasticity

View More Questions