The voltage amplification \( A_V \) in a CE configuration is given by the formula: \[ A_V = \beta_{{ac}} \times \frac{R_C}{R_B} \] Where: - \( \beta_{{ac}} = 1.4 \) - \( R_C = 10 \, \Omega \) - \( R_B = 8 \, \Omega \) Substitute the values: \[ A_V = 1.4 \times \frac{10}{8} = 1.75 \] Thus, the voltage amplification is 1.75.
Final Answer: 1.75.
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))