The voltage amplification \( A_V \) in a CE configuration is given by the formula: \[ A_V = \beta_{{ac}} \times \frac{R_C}{R_B} \] Where: - \( \beta_{{ac}} = 1.4 \) - \( R_C = 10 \, \Omega \) - \( R_B = 8 \, \Omega \) Substitute the values: \[ A_V = 1.4 \times \frac{10}{8} = 1.75 \] Thus, the voltage amplification is 1.75.
Final Answer: 1.75.
An inductor and a resistor are connected in series to an AC source of voltage \( 144\sin(100\pi t + \frac{\pi}{2}) \) volts. If the current in the circuit is \( 6\sin(100\pi t + \frac{\pi}{2}) \) amperes, then the resistance of the resistor is: