Question:

When a certain metallic surface is illuminated with monochromatic light of wavelength \( \lambda \), the stopping potential for photoelectric current is \( V_0 \). When the same surface is illuminated with a light of wavelength \( 2\lambda \), the stopping potential is \( V_1 \). The threshold wavelength for this surface to photoelectric effect is

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In photoelectric effect, the stopping potential is inversely proportional to the wavelength of the incident light.
Updated On: Jan 6, 2026
  • \( \lambda_0 \)
  • \( 6\lambda \)
  • \( \frac{4\lambda}{3} \)
  • \( \frac{3\lambda}{4} \)
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The Correct Option is A

Solution and Explanation


Step 1: Using the photoelectric equation.
The stopping potential is related to the wavelength of the incident light. When the wavelength doubles, the stopping potential also changes accordingly. We calculate the threshold wavelength for the given condition.

Step 2: Conclusion.
The threshold wavelength is \( \lambda_0 \), corresponding to option (1).
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