$\frac1{2} \frac{(stress)}{Y}$
$\frac{(stress)^2}{2Y}$
When a body is strained, the energy stored per unit volume (also known as the strain energy density) is related to the stress and strain through Young's modulus \( Y \).
The formula for the energy stored per unit volume is derived from the relationship between stress and strain, and it is given by: \[ \text{Energy per unit volume} = \frac{1}{2} \times \text{stress} \times \text{strain} \] Since stress (\( \sigma \)) is related to Young's modulus (\( Y \)) and strain (\( \epsilon \)) by: \[ \sigma = Y \times \epsilon \] Therefore, strain (\( \epsilon \)) can be written as: \[ \epsilon = \frac{\sigma}{Y} \] Substituting this into the energy formula: \[ \text{Energy per unit volume} = \frac{1}{2} \times \sigma \times \frac{\sigma}{Y} = \frac{1}{2} \times \frac{\sigma^2}{Y} \] Thus, the energy stored per unit volume is: \[ \text{Energy per unit volume} = \frac{1}{2} \times \frac{\text{stress}^2}{Y} \]
Correct Answer: (E) \( \frac{(stress)^2}{2Y} \)
The elastic behavior of material for linear stress and linear strain, is shown in the figure. The energy density for a linear strain of 5×10–4 is ____ kJ/m3. Assume that material is elastic up to the linear strain of 5×10–4
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: