Question:

When a block of mass \(M\) is suspended by a long wire of length \( L\), the length of the wire becomes \((L+l)\). The elastic potential energy stored in the extended wire is:

Updated On: Apr 14, 2025
  • Mgl
  • MgL
  • \(\frac12Mgl\)
  • \(\frac12MgL\)
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The Correct Option is C

Solution and Explanation

The correct option is (C) :\(\frac12MgL\)
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