When 3 is subtracted from each of the given 'n' numbers, then the sum of the numbers so obtained is 84. When 8 is added to each of the given 'n' numbers, then the sum of the resulting numbers is 216. The mean of the given 'n' numbers is:
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When comparing changes to a total due to constant addition or subtraction, use system of equations to find original values.
Let the sum of the original 'n' numbers be \( S \).
Then,
\[
S - 3n = 84 \quad \text{(i)}
S + 8n = 216 \quad \text{(ii)}
\]
Subtracting (i) from (ii):
\[
(S + 8n) - (S - 3n) = 216 - 84
11n = 132 \Rightarrow n = 12
\]
Substitute back into (i):
\[
S - 36 = 84 \Rightarrow S = 120
\]
Mean \( = \frac{S}{n} = \frac{120}{12} = 10 \)
Correct value: 10