To determine the increasing order of basic strength, we need to consider the factors that affect the basicity of amines:
Let's analyze the given compounds:
C2H5NH2 (Ethylamine): A primary aliphatic amine.
(C2H5)2NH (Diethylamine): A secondary aliphatic amine.
(C2H5)3N (Triethylamine): A tertiary aliphatic amine.
C6H5NH2 (Aniline): An aromatic amine.
Based on these factors:
Aniline (C6H5NH2) is the least basic due to resonance delocalization.
Among the aliphatic amines, secondary amines are generally the most basic due to a combination of inductive and solvation effects.
Primary amines are less basic than secondary amines but more basic than tertiary amines due to steric hindrance in tertiary amines.
Therefore, the increasing order of basic strength is:
C6H5NH2 < C2H5NH2 < (C2H5)3N < (C2H5)2NH
The correct answer is:
Option 2: C6H5NH2 < C2H5NH2 < (C2H5)3N < (C2H5)2NH