To determine the volume occupied by 2 moles of an ideal gas at STP (Standard Temperature and Pressure), we must use the ideal gas law, specifically noting the molar volume of a gas at STP.
At STP, which is defined as a temperature of 0°C (273.15 K) and a pressure of 1 atmosphere (atm), one mole of an ideal gas occupies a volume of 22.4 liters (L).
Given:
Moles of gas = 2 moles
Molar volume at STP = 22.4 L/mol
To find the total volume occupied by 2 moles of the gas, multiply the number of moles by the molar volume:
Volume = Number of Moles × Molar Volume
Volume = 2 moles × 22.4 L/mol = 44.8 L
Therefore, 2 moles of an ideal gas at STP occupy a volume of 44.8 liters.