Step 1: Understand the given quadratic expression.
The quadratic expression is:
\[
9x^2 + 3kx + 4
\]
We need to find the values of \( k \) that will make this expression a perfect square.
Step 2: General form of a perfect square.
For a quadratic expression to be a perfect square, it must be expressible as the square of a binomial, i.e.,
\[
(ax + b)^2 = a^2x^2 + 2abx + b^2
\]
Comparing this with the given quadratic expression, we can see that:
\[
a^2 = 9 \quad \text{and} \quad b^2 = 4
\]
Thus, \( a = 3 \) (since \( a^2 = 9 \), so \( a = 3 \)) and \( b = 2 \) or \( b = -2 \) (since \( b^2 = 4 \), so \( b = 2 \) or \( b = -2 \)).
Step 3: Compare the linear term.
The linear term of the perfect square expansion is:
\[
2abx
\]
In our case, \( a = 3 \), so:
\[
2ab = 2 \times 3 \times b = 6b
\]
Now compare this with the linear term of the given expression, which is \( 3kx \). For the expression to be a perfect square, we must have:
\[
6b = 3k
\]
Therefore, \( k = 2b \).
Step 4: Solve for \( k \).
Since \( b = 2 \) or \( b = -2 \), we have two possible values for \( k \):
- If \( b = 2 \), then \( k = 2 \times 2 = 4 \).
- If \( b = -2 \), then \( k = 2 \times (-2) = -4 \).
Step 5: Conclusion.
The values of \( k \) that make the expression a perfect square are \( k = 4 \) and \( k = -4 \).
Final Answer:
The correct option is (D): ± 4.