Question:
What is ‘Y’ in the following reaction sequence?
What is ‘Y’ in the following reaction sequence?
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Kolbe’s reaction introduces a carboxylic acid group ortho to the hydroxyl group on phenol. Acetylation of the –OH group yields aspirin (acetylsalicylic acid).
Updated On: Jun 3, 2025
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The Correct Option is B
Solution and Explanation
Step 1: Phenol reacts with NaOH and CO$_2$ to form salicylic acid via Kolbe's reaction (X = salicylic acid).
Step 2: Salicylic acid reacts with acetic anhydride ((CH$_3$CO)$_2$O) in the presence of acid (H$^+$) to yield aspirin (Y).
This transformation involves acetylation of the hydroxyl group of salicylic acid, forming acetylsalicylic acid (aspirin), which corresponds to Option (2).
Step 2: Salicylic acid reacts with acetic anhydride ((CH$_3$CO)$_2$O) in the presence of acid (H$^+$) to yield aspirin (Y).
This transformation involves acetylation of the hydroxyl group of salicylic acid, forming acetylsalicylic acid (aspirin), which corresponds to Option (2).
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