When a liquid rises in a capillary tube, the height of the rise is inversely proportional to the density of the liquid and directly proportional to the surface tension.
The angle of contact (\( \theta \)) of the liquid with the capillary wall is also related to the density of the liquid. For a liquid with higher density, the angle of contact tends to be greater. In this case, we have three liquids with densities \( P_1 \), \( P_2 \), and \( P_3 \) such that \( P_1<P_2<P_3 \). According to the relationship between the angle of contact and density: - The liquid with the lowest density (\( P_1 \)) will have the highest angle of contact. - The liquid with the highest density (\( P_3 \)) will have the smallest angle of contact.
Therefore, the relation between the angles of contact is: \[ 0<\theta_3<\theta_2<\theta_1<\frac{\pi}{2} \]
Thus, the correct answer is option A.
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure.
The angular velocity of the system after the particle sticks to it will be: