What is the percentage of carbon in ethanol (\(C_{2}H_{5}OH\)) ?
(Atomic masses: C = 12, H = 1, O = 16)
Step 1: Calculate the molar mass of ethanol \(C_{2}H_{5}OH\):
\[ = 2 \times 12 + 6 \times 1 + 1 \times 16 = 24 + 6 + 16 = 46 \, \text{g/mol} \]
Step 2: Calculate the total mass of carbon in one mole of ethanol:
\[ = 2 \times 12 = 24 \, \text{g} \]
Step 3: Calculate the percentage of carbon:
\[ \text{Percentage of C} = \frac{24}{46} \times 100 = 52.17% \approx 52.2% \]
Step 4: Hence, the percentage of carbon in ethanol is approximately 52.2%.
LIST I | LIST II | ||
A. | \(K_2SO_4(aq)\) with 60% dissociation | I. | \(i =3.7\) |
B. | \(K_3[Fe(CN)_6](aq)\) with 90% dissociation | II. | \(i= 1.8\) |
C. | \(AlCl_3 (aq)\) with 80% dissociation | III. | \(i=2.2\) |
D. | \(K_2HgI_4 (aq)\) with 40% dissociation | IV. | \(i= 3.4\) |