What is the number of different messages that can be represented by three a’s and two b’s?

Question

cdquestions Admin · Accepted Answer

Explanation:
We know that:Suppose a set of

n

objects has

n_{1}

of one kind of object,

n_{2}

of a second kind,

n_{3}

of a third kind, and, So, on with

n = n_{1} + n_{2} + n_{3} + \dots + n_{k}

then the number of distinguishable permutations of the

n

objects is:

= \frac{n!}{n_{1}! \times n_{2}! \times n_{3}! \dots \dots . n_{k}!}

Given: Three a’s and two b’saaabbTotal number

= 3 + 2 = 5

In the set of 5 words has 3 words of one kind and 2 words of the second kind.Therefore, number of different messages that can be represented by three a's and two b's,

= \frac{5!}{3! 2!} = 10

Hence, the correct option is (D).

Answer

Answer

Answer

Answer

What is the number of different messages that can be represented by three a’s and two b’s?

The Correct Option is D

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