Question

What is the number of atoms in $12.08 \times 10^{23}$ unit cells if an element crystallises in bcc structure?

• A. $4.838 \times 10^{24}$
• B. $2.08 \times 10^{22}$
• C. $2.416 \times 10^{24}$
• D. $1.208 \times 10^{23}$

Hint:

Atoms per unit cell: SC = 1, BCC = 2, FCC = 4.

Answer 1

The Correct Option is C

Step 1: Recall atoms per unit cell in BCC.
In a body-centred cubic (bcc) structure, each unit cell contains 2 atoms.
Step 2: Multiply by number of unit cells.
Number of unit cells given $= 12.08 \times 10^{23}$
Step 3: Calculate total atoms.
\[ \text{Total atoms} = 2 \times 12.08 \times 10^{23} \]
\[ \text{Total atoms} = 24.16 \times 10^{23} = 2.416 \times 10^{24} \]
Step 4: Conclusion.
The total number of atoms present is $2.416 \times 10^{24}$.